2=20/(x^2+2)

Solution for 2=20/(x^2+2) equation:

2=20/(x^2+2)

We move all terms to the left:

2-(20/(x^2+2))=0


Domain of the equation: (x^2+2))!=0

x∈R


We multiply all the terms by the denominator


-(20+2*(x^2+2))=0


We calculate terms in parentheses: -(20+2*(x^2+2)), so:

20+2*(x^2+2)

determiningTheFunctionDomain
2*(x^2+2)+20

We multiply parentheses

2x^2+4+20

We add all the numbers together, and all the variables

2x^2+24

Back to the equation:

-(2x^2+24)


We get rid of parentheses

-2x^2-24=0

a = -2; b = 0; c = -24;
Δ = b2-4ac
Δ = 02-4·(-2)·(-24)
Δ = -192
Delta is less than zero, so there is no solution for the equation